8y^2+118y+60=0

Solution for 8y^2+118y+60=0 equation:

8y^2+118y+60=0

a = 8; b = 118; c = +60;
Δ = b2-4ac
Δ = 1182-4·8·60
Δ = 12004
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12004}=\sqrt{4*3001}=\sqrt{4}*\sqrt{3001}=2\sqrt{3001}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(118)-2\sqrt{3001}}{2*8}=\frac{-118-2\sqrt{3001}}{16}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(118)+2\sqrt{3001}}{2*8}=\frac{-118+2\sqrt{3001}}{16}
$